What is the value of d/dx (6/x^4 + 1/x^2) at x = -1 ?

\frac{d}{dx}\left(\frac{1+x^4+x^6}{x^2+x+1}\right)=\frac{4x^7+5x^6+8x^5+3x^4+4x^3-2x-1}{\left(x^2+x+1\right)^2}

Step-by-step explanation:

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step-by-step explanation:

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-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0