Due to inclement weather, the pilot of a plane slows down the plane’s regular flying rate by 25%. This result to an additional 1.5 hours in covering the 3,000km distance to its regular time required for the trip. Find the regular rate of the trip.

The regular speed or rate of the trip is 2111.1 km per hour.

Suppose that ; speed of plane is =  S

Due to inclement weather the pilot slow down the plan rate by 25%

then new speed = S-25%  of S = 0.75S

Time taken = t

New time taken = t+1.5 hours

Total distance covered = 3000 km

Initial speed of the plane was,

Time t can be written as,

So, the new speed will be,

So, the regular speed of the trip can be calculated as,

Solving further,

Therefore, the regular speed or rate of the trip is 2111.1 km per hour.

For more details, refer to the link:

link

Normal speed = 711.11 km/h (Approx)

Step-by-step explanation:

Assume;

Normal speed = x

New speed = x - 25% of x = 0.75 x

Time taken = t

New time taken = t + 1.5 hour

Total distance

Computation:

Total distance = 3,200 km

Speed = Distance/Time

x = 3200 / t

t = 3200/x

so,

0.75 x = 3200 / (t+1.5)

0.75 x = 3200 / (3200/x+1.5)

0.75 x = 3200 / [(3200 + 1,5x)x]

x = 711.11 km/h

Normal speed = 711.11 km/h (Approx)

answer: 4

step-by-step explanation:

where's the diagrams?