The number of students using the ATM on campus daily is normally distributed with a mean of 240 and a standard deviation of 50. Based upon a random sample of 100 days, what is the probability that the ATM usage averaged more than 247 students per day

The probability is 0.080757

Step-by-step explanation:

We start by calculating the z-score

z-score = (x-mean)/SD/ √n

In this case;

x = 247 , mean = 240, SD = 50 and n = 100

z-score = (247-240)/50/√100

z-score = 7/50/10

= 7/5 = 1.4

So the probability we want to calculate is;

P( x > 1.4)

we can use the standard normal distribution table for this

P(x > 1.4) = 0.080757

one that is bigger than 3 1/2

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all