The differential equation y+y2=(y5+x)y′ can be written in differential form: M(x, y)dx+N(x, y)dy=0 where M(x, y)= , and N(x, y)= . The term M(x, y)dx+N(x, y)dy becomes an exact differential if the left hand side above is divided by y2. Integrating that new equation, the solution of the differential equation is =C.

M? aoc=96 ? space, m, angle, a, o, c, equals, 96, degree \qquad m \angle boc = 8x - 67^\circm? boc=8x? 67 ? space, m, angle, b, o, c, equals, 8, x, minus, 67, degree \qquad m \angle aob = 9x - 75^\circm? aob=9x? 75 ? space, m, angle, a, o, b, equals, 9, x, minus, 75, degree find m\angle bocm? bocm, angle, b, o, c: