Someone listed all the numbers from 0 to 99999 in increasing order. Then he crossed out all the numbers where some other digit(s) besides 0 and 1 were used. A How many numbers does he have left?

he has 32 numbers left.

Step-by-step explanation:

The first given number is 0.

1-digit number 1 *1 (=1)

2-digit numbers (1 and , 2 choices for 2nd digit). 1*2 (= 2)

3-digit numbers ( 1, 2 and first choice for 3.). 1*2*2 (= 4)

4-digit numbers (we join our answer for 1,2 and 3 with first choice of 4). 1*2*2*2 (= 8)

5-digit numbers s (1, 2, 3rd, 4th & first Choice of 5th digits). 1*2*2*2*2 (= 16)

Total number range from 0 to 1.

1 + 1 + 2 + 4 + 8 + 16

= 2^5

= 32.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3