[4F-13] Suppose that waiting time until the next claim is exponentially distributed with mean of 4 days. For last 2 days, there have been no claims. Calculate the probability that waiting time until the next claim will exceed 4 more days (6 days in total). (Round to 4 decimals)

The probability that waiting time until the next claim will exceed 4 more days i.e. P(X>6/X>2) = 0.3679

Step-by-step explanation:

From the given information:

Let consider X to be a random variable that follows an exponential distribution fo the waiting time.

Then; since the mean is distributed between 1 - 4 days

Thus:

The objective is to determine:

Recall that:

= 0.3678794412

To four decimal places; we have:

The probability that waiting time until the next claim will exceed 4 more days i.e. P(X>6/X>2) = 0.3679

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6