Lines AD and BC are parallel. A

D

150

45°

B

F

Find the measures of the three angles in triangle in ADE.

Angle ADE -

degrees

Angle DAE =

degrees

Angle DEA

_degrees

T

*see attachment for the missing figure

Angle ADE = 45°

Angle DAE = 30°

Angle DEA = 105°

Step-by-step explanation:

Since lines AD and BC are parallel, therefore:

Given that angle Angle CBE = 45°,

Angle ADE = Angle CBE (alternate interior angles are congruent)

Angle ADE = 45° (Substitution)

Angle DAE = Angle ACB (Alternate Interior Angles are congruent)

Angle ACB = 180 - 150 (angles on a straight line theorem)

Angle ACB = 30°

Since angle DAE = angle ACB, therefore:

Angle DAE = 30°

Angle DEA = 180 - (angle ADE + angle DAE) (Sum of angles in a triangle)

Angle DEA = 180 - (45 + 30) (Substitution)

Angle DEA = 180 - 75

Angle DEA = 105°

what are you trying to solve here

step-by-step explanation:

m∠a is 90°

m∠b is 40°