There is a frog at the bottom of a 20 foot well. he climbs up 5 feet during the day but at night he falls asleep and slips down 4 feet. at this rate how many days will it take it to climb out of the well.

20days

Step-by-step explanation:

He climbs 5ft during the day and fell 4ft at night. Therfore the difference is 1ft and the well is 20ft..so it implies that the rate at which it ft increases a day is 1ft will be multiplied by the foot of the well which is 20ft

1×20=20days

the answer is "add 2y and y"

step-by-step explanation:

you need to collect the like terms first.