In ΔRST, \text{m}\angle R = (5x-11)^{\circ}m∠R=(5x−11) ∘
, \text{m}\angle S = (3x-3)^{\circ}m∠S=(3x−3)
∘
, and \text{m}\angle T = (3x+18)^{\circ}m∠T=(3x+18)
∘
. Find \text{m}\angle R. m∠R.

∘(5x−11)+(3x−3)+(3x+18)=180

(5x+3x+3x)+(−11−3+18)=180    Group like terms

11x+4= 180   combine like terms

     -4   -4

  11x=176

11x=176    divide both sides by 11

11      11

x=16       found x

m∠R=5x−11=5(16)−11=69    Final answer

Step-by-step explanation:

the solution is 12x-6y

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3