Suppose f(x)= 2 ^ x - 3x and g(x = 1 - 2x. Find each of the following functions. a. (f + g)(x) b. (f- g)(x)

(f+g)(x)=2^x-5x+1 and

(f-g)(x)=2^x-x-1

Step-by-step explanation:

(f+g)(x)=2^x-3x+1-2x

=2^x-5x+1

(f-g)(x)=2^x-3x-1+2x2x

=2^x-x-1

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x