There are 12 coins ; dimes and quarters. The number of dimes is 2 more than the number of quarters. A. $2.25
B. $2.10
C. $2.50
D. $1.95
E. $1.65
F. $1.80
You have 15 coins; dimes and quarters. The number of quarters is twice as many as dimes. Find the total value of the coins.
A. $2
B. $3.25
C. $3.50
D. $2.50
E. $2.25
F. $3

D.  $1.95

F.  $3

Step-by-step explanation:

dimes:  x + 2

quarters:  x

x + 2 + x = 12

2x + 2 = 12

2x = 10

x = 5

dimes:  x + 2 = 5 + 2 = 7

quarters:  x = 5

Total value: (7 * .10) + (5 * .25) = $1.95

dimes:  x

quarters:  2x

x + 2x = 15

3x = 15

x = 5

dimes:  x = 5

quarters:  2x = 2(5) = 10

Total value: (5 * .10) + (10 * .25) = $3

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.