Kashawn works at a pizzeria for $10.00 an hour and he can work a maximum of 10 hours a day. If represents the number of hours Kashawn works while () represents his pay each day, which of the following best represents the domain?

He wins $10.00 per hour.

He can work a maximum of 10 hours per day.

x is the number of hours that he works, and f(x) is his daily pay.

f(n) = $10.00*n

First, let's find the domain:

We know that, at a maximum, he can work 10 hours per day.

The set of possible values of x, the domain, is:

D: 0 ≤ x ≤ 10

From this, we can also find the range, because f(x) is a linear function with a positive slope, the minimum in the domain will map in the minimum in the range, and the same for the maxima.

Then the range will be:

R: f(0) ≤ f(x) ≤ f(10)

    $10*0 ≤ f(x) ≤ $10*10

      $0 ≤ f(x) ≤ $100.

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

yes the data was not prsented

step-by-step explanation: