Can you help me is monomials

Section 2.4

8x^2y : 2x : 2y = 2x

This is because 8x^2y divided over 2x leads to 4xy. Dividing 4xy over 2y leads to 2x.

15x^6y^3 : 5y^2x^3 = 3x^3y

Note how 15 divided by 5 is 3

Also, x^6 divided by x^3 is x^3. You subtract the exponents.

Similarly, y^3 divided by y^2 is y^1 = y.

16y^5x^3z : -4zyx = -4y^4x^2

Divide the coefficients to get 16/(-4) = -4

The y terms divide to (y^5)/(y) = y^4. Subtract the exponents.

The x and z terms are handled the same way.

-8x^2 : 2x = -4x

We follow the same steps as before. This time -8/2 = -4 is the new coefficient. The x terms divide to (x^2)/x = x where x is nonzero.

-6xz : -2zx = 3

The coefficients divide to (-6)/(-2) = 3

The x and z terms cancel out when we divide them.

3y^2x : xy^2 = 3

The y^2x expression is the same as xy^2, so when we divide these terms they cancel.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?