The length of a rectangle is 4 more than half the width. Which equation could represent the area of the rectangle in terms of the width?

let length be x and breadth be y

by question

L=4×1/2×B

L = 2B

now

Area of rectangle=L×B

2B ×B

2B^2

Is it correct? ,I actually tried to solve it

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )