A bus has velocity 20 m/s towards east and another bus has velocity 15 m/s in west direction. If they start to move from a point simultaneously, what distances do they cover in 2 minute?

The first bus has covered 2,400 m and the second bus has covered 1,800 m. They are separated by 4,200 m

Step-by-step explanation:

Constant Velocity Motion

A bun has a velocity of 20 m/s towards the east. It means it travels 20 meters each second in that direction. Assuming the east direction is positive, the distance traveled by this bus can be calculated as follows:

X1=20*t

Where t is the time in seconds.

Similarly, the distance traveled by the second bus towards the west is:

X2=-15*t

Note the negative sign because the direction points at the negative reference.

After 2 minutes = 120 seconds have passed, the distance of each bus is

X1= 20*120=2,400 m

X2=-15*120 = 1,800 m

They are separated by 2,400-(-1,800) = 4,200 m

The first bus has covered 2,400 m and the second bus has covered 1,800 m. They are separated by 4,200 m

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

won't that be plagrisim thought?

step-by-step explanation: