Tutoring Services: The Community College Survey of Student Engagement reports that 46% of the students surveyed rarely or never use peer or other tutoring resources. Suppose that in reality 40% of community college students never use tutoring services available at their college. In a simulation we select random samples from a population in which 40% do not use tutoring. For each sample we calculate the proportion who do not use tutoring. If we randomly sample 500 students at a time, what will be the mean and standard error of the sampling distribution of sample proportions

Mean = 0.40 and  standard error = 0.0219 of the sampling distribution of sample proportions.

Step-by-step explanation:

Given : The proportion of community college students never use tutoring services available at their college: p= 0.40

Mean of the sampling distribution of sample proportions  = p = 0.40

Since sample size : n= 500

Standard error =

Hence, Mean = 0.40 and  standard error = 0.0219 of the sampling distribution of sample proportions.

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign

to find the total number of combinations, multiply the quantity of each item by each other:

2 pairs of shoes x 3 pairs of shorts = 6 different combinations.