For 50 randomly selected speed dates, attractiveness ratings by males of their female date partners (x) are recorded along with the attractiveness ratings by females of their male date partners (y); the ratings range from 1 to 10. The 50 paired ratings yield , , r, P-value, and x. Find the best predicted value of (attractiveness rating by female of male) for a date in which the attractiveness rating by the male of the female is x. Use a significance level.

This question is incomplete, the complete question is;

For 50 randomly selected speed dates, attractiveness ratings by males of their female date partners (x) are recorded along with the attractiveness ratings by females of their male date partners (y); the ratings range from 1 to 10.

The 50 paired ratings yield x = 6.3, y = 6.0, r = -0.194, P-value = 0.176, and y^ = 7.40 - 0.218x.

Find the best predicted value of (attractiveness rating by female of male) for a date in which the attractiveness rating by the male of the female is x.

Use a significance level.

the best predicted value of y^ when x=8 is ?

( round your answer to one decimal place as needed.

The best predicted value of y ^ when x equals 8 is 5.7

Step-by-step explanation:

From the information it is clear that equation for the regression line is

y^ = 7.40 - 0.218x.

where y^ represents the attractiveness rating by female of male partners and  x represents the attractiveness rating by male of female partners.

The predicted value of y ^  when x equals 8 is obtained by substituting the value of x with 8 in the given regression equation.

The predicted value of y^  when x equals 8 is obtained below:;

The regression equation is y^ = 7.40 - 0.218x  

Substitute x = 8x=8

y^  =7.40 − 0.218x

=7.40 − 0.218(8)

=7.40 − 1.744

= 5.656  ≃ 5.7

therefore The best predicted value of y ^ when x equals 8 is 5.7

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%