For an F-distribution, find (a) f0.05 with v1 = 7 and v2 = 15; (b) f0.05 with v1 = 15 and v2 = 7: (c) f0.01 with v1 = 24 and v2 = 19; (d) f0.95 with v1 = 19 and v2 = 24; (e) f0.99 with v1 = 28 and v2 = 12.

In this exercise we have to calculate the distribution of F , so for certain values we will have:

A.)

B.)

C.)

D.)

E.)  

Using the F - distribution table find :

(a) For F equal to 0.05, we have:

b)For F equal to 0.05, we have:

(c)For F equal to 0.01, we have:

(d)For F equal to 0.95, we have:

(e)For F equal to 0.99, we have:

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A.) 2.71

B.) 3.51

C.) 2.92

D.) 0.47

E.) 0.35

Step-by-step explanation:

Using the F - distribution table :

find :

(a) f0.05 with v1 = 7 and v2 = 15

α = 0.05 ; v1 = 7 ; v2 = 15

F0.05 = 2.7066

b) f0.05 with v1 = 15 and v2 = 7:

α = 0.05 ; v1 = 15 ; v2 = 7

F0.05 = 3.5107

(c) f0.01 with v1 = 24 and v2 = 19;

α = 0.01 ; v1 = 24 ; v2 = 19

F0.01 = 2.92

(d) f0.95 with v1 = 19 and v2 = 24;

F0.95, (v1 = 19, v2= 24) = 1/[(F(1-0.95), v1=19, v2= 24]

Hence,

1/F0.05, v1 = 19, v2 = 24

= 0.47 (F distribution calculator)

(e) f0.99 with v1 = 28 and v2 = 12

F0.99, (v1 = 28, v2= 12) = 1/[(F(1-0.99), v1=28, v2= 12]

Hence,

1/F0.01, v1 = 28, v2 = 12

= 0.35 (F distribution calculator)

b

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

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