60 % of members of a student club are sophomores. 40 % of the sophomores plan to graduate in May. What is the probability that a member of the club is both a sophomore and plans to graduate in May?

0.24

Step-by-step explanation:

Suppose that we have N members in the student club.

N represents the 100% in this case.

We know that 60% of them are sophomores.

Then the number of sophomores will be:

(60%/100%)*N = 0.6*N

there are 0.6*N sophomores

Out of the 0.6*N sophomores, 40% plans to graduate in May.

Now we take 0.6*N as the 100% (because the 40% is applied only to the sophomores).

Then the number of sophomores that want to graduate in May is:

(40%/100%)*0.6*N = 0.4*0.6*N = 0.24*N

Now, the probability that a random student is a sophomore and also wants to graduate in May is equal to the quotient between the number of sophomores that want to graduate in May and the total number of members in the club.

P = (0.24*N)/N = 0.24

Then the probability that a member is both a sophomore and plans to graduate in May is 0.24

answer: correct

step-by-step explanation: