a square with a side length of 2 units is drawn on the coordinate plane with a vertex at the origin. Which shows a dilation of the square by a scale factor of 2

Step-by-step explanation:

From the figure attached,

ABCD is a square with vertices as,

A(-2, 0), B(-2, 2), C(0, 2) and D(0, 0)

If the given square is dilated by a scale factor of 2 and the center of dilation is the point D (origin).

Rule for the dilation of a point by a scale factor k is,

(x, y) → (kx, ky)

By this rule,

A(-2, 0) → A'(-4, 0)

B(-2, 2) → B'(-4, 4)

C(0, 2) → C'(0, 4)

D(0, 0) → D'(0, 0)

Now we can plot these points to get the image square (dilated figure) as given the figure attached.

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!