I rlly need help; finding angles

∠1 = 35                  ;      ∠2 = 65       ;     ∠3 = 29       ;      ∠4 = 115  

∠5 = 65               ;       ∠6 = 36       ;   ∠7 = 144

Step-by-step explanation:

∠4 = 115                              {Vertically opposite angles}

∠5 + 115 = 180                  {linear pair}

         ∠5 = 180 - 115

        ∠5 = 65

∠2 = ∠5         {Vertically opposite angles}

∠2 = 65

∠1 + 80 +∠2 = 180   {Angle sum property of triangle}

∠1 + 80 + 65=180

       ∠1 + 145 = 180

               ∠1 = 180 - 145

∠1 = 35

∠5 + ∠7 + 90 + 61 = 360   {angle sum property of quadrilateral}

65 + ∠ 7 + 90 + 61 = 360

          ∠7 + 216      = 360

                    ∠7      = 360 - 216

                       ∠7 = 144

∠6 + ∠ 7 = 180   {linear pair}

∠6 + 144 = 180

          ∠6 = 180 - 144

          ∠6 = 36

∠3 + ∠4 +∠ 6 = 180        {angle sum property of triangle}

∠3 + 115 + 36 = 180

      ∠3 + 151  = 180

               ∠3 = 180 - 151

               ∠3 = 29

i understand 100% 10/10 hit or miss?

step-by-step explanation:

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.