An object placed in a graduated cylinder raised the volume from 12.2 mL to 14.5 mL. Find the volume of the object.

2.3 mL

Step-by-step explanation:

This is called finding the volume by displacement. By subtracting the final volume and the initial volume you can determine how much the volume changed when the object was added. That change in voulme represents the volume of the object, so in this case:\

14.5-12.2 = 2.3 mL

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b