Given the piecewise function defined below, answer the questions at the bottom of the page regarding the continuity and differentiability of f at x = 1.
for
f(3) =
6 ln(2 – x) – 4
- 3x²
3 < 1
3 > 1
for
lim f(x) =
lim f(s)
f(1)
2-1
21-
lim f'(x)
lim f'(x) =
2-1
2-1-
So the function f(x) is
at = 1.
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Which expression is equivalent to the expression below? (6c^2 + 3c) / (-4c + 2) / (2c + 1) / (4c - 1)a. 3c(2c-1) / (2c + 1)b. -3c(2c-1)^2 / (2c + 1)^2c. 3cd. -3c(just took the test its d. -3c)

Drag and drop the answers into the boxes to complete this informal argument explaining how to derive the formula for the volume of a cone. since the volume of a cone is part of the volume of a cylinder with the same base and height, find the volume of a cylinder first. the base of a cylinder is a circle. the area of the base of a cylinder is , where r represents the radius. the volume of a cylinder can be described as slices of the base stacked upon each other. so, the volume of the cylinder can be found by multiplying the area of the circle by the height h of the cylinder. the volume of a cone is of the volume of a cylinder. therefore, the formula for the volume of a cone is 1/3 1/2 1/3πr^2h 1/2πr^2h πr^2h πr^2

Which expression is equivalent to 5r674 pression is equivalent to see lo 5r614) 4r322,4 ) 5 ( 2 5t5 |