A basketball player claims to make 47% of her shots from the field. We want to simulate the player taking sets of 10 shots, assuming that her claim is true. Twenty-five repetitions of the simulation were performed. The simulated number of makes in each set of 10 shots was recorded on the dot plot below. What is the approximate probability that a 47% shooter makes 5 or more shots in 10 attempts

0.9 or 90%

Step-by-step explanation:

The probability of shot is 47%

The probability of no shot is 100 -47 = 53%

The dot plot is made from the 10 repeated shots which recorded 25 scores.

The number of dots on the fifth tick is 9 of 10 shots

therefore; 9/10 = 0.9, which 90 in percentage.    

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)