Find three consecutive integers such that the sum of the first and the
second integer is three more than the
third integer.

9514 1404 393

  4, 5, 6

Step-by-step explanation:

Let x represent the middle one. Then the sum of the first two is ...

  (x -1) +x

And we want that to be 3 more than the third:

  (x -1) +x = (x +1) +3

  2x = x +5 . . . . . . . . . add 1, simplify

  x = 5 . . . . . . . . . . . . . subtract x

Since 5 is the middle integer, the three integers are ...

  4, 5, 6

answer:   n ≤ -3 or n < -5

step-by-step explanation:

-5 + 2n ≥ -11

+5             +5

2n ≥ -6

2/2 ≤ -6/2

n ≤ -3

-6 - 10n > 44

+6           +6

-10n > 50

-10/-10 50/-10

n < -5

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: