Hel A seismologist places two recording devices 340 meters apart at points A and B. To check the calibration, an explosive is detonated between the devices 90 meters from point A. The seismologist notes the time the explosions register on the devices, and calculates the difference. The seismologist will detonate a second explosion east of point A. How far east should the second explosion be positioned so that the measured time difference is the same as for the first explosion?

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

for future students the answer is b

hope i

-lavira: )