3. The perimeter of a square is 28 feet. If you increase the length by 2 feet and decrease the width by 1 foot, what is the area of the new figure? A.54 B.40 C.48 D.36

The correct options is;

A. 54

Step-by-step explanation:

The given parameters are;

The perimeter of the square = 28 feet

The increase in the dimension of the length of square = 2 feet

The decrease in the dimension of the width of square = 1 feet

We answer as follows;

Let the length of the side of the square = L

The formula for the perimeter of a square = 4 × L

∴ 4 × L = 28 feet

L =28/4 = 7 feet

L = 7 feet

After applying the given modifications, we have;

The new length, L₁ = L + 2 feet = 7 feet  + 2 feet = 9 feet

The new length, L₁ = 9 feet

The new width, W = L - 1 feet = 7 feet - 1 feet = 6 feet (The width and the length, L of a square are equal)

The new width, W = 6 feet

Therefore;

The area of the new figure = The new length × The new width

Substituting the values gives;

The area of the new figure = 9 feet × 6 feet = 54 feet².

The area of the new figure = 54 feet².

step-by-step explanation:

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step-by-step explanation: