Mitchell needs to buy some wood to build a rectangular box that is 12 inches long 8 I ches wide and 10 inches high a net of the box is shown how many square inches of wood would Mitchell need to build the box

592 in²

Step-by-step explanation:

Given

Length of the box L = 12 inches

Width W = 8 inches

height H = 10inches

Required

Surface Area of the box

Surface area of the rectangular boss = 2(LW + LH + WH)

Substitute the given values

Surface area = 2(12(8)+12(10)+8(10))

Surface Area = 2(96+120+80)

Surface Area = 2(96+200)

Surface area = 2(296)

Surface area = 592 in²

Hence  592 in² of wood would be needed by Mitchell to build the box

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x