If one fly ball is randomly chosen from this distribution, what is the probability that this ball traveled fewer than 204 feet

Complete question is;

Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 244 feet and a standard deviation of 44 feet. Let X = distance in feet for a fly ball.

If one fly ball is randomly chosen from this distribution, what is the probability that this ball traveled fewer than 184 feet? (Round your answer to four decimal places.)

0.1814

Step-by-step explanation:

We are given;

Mean; μ = 244

Standard deviation; σ = 44

Test score; x' = 204

z-score = (x' - μ)/σ

z = (204 - 244)/44

z = -0.91

Thus, probability that X travelled fewer than 184 ft is;

P(X < 184) = P(Z = -0.91)

From z-distribution table attached, P = 0.18141

Thus; P(X < 184) ≈ 0.1814

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

answer: 34rtyj,jkhtyetwrhyjeuiejnbhdfknbkguxfrbhkfdbjvkmbd,kvbsd.kxjvbhjnfbgjxdfn

step-by-step explanation: