The diameters of ball bearings are distributed normally. The mean diameter is 52 millimeters and the standard deviation is 4 millimeters. Find the probability that the diameter of a selected bearing is greater than 57 millimeters. Round your answer to four decimal places.

0.1057

Step-by-step explanation:

We solve using z score formula.

z = (x-μ)/σ, where

x is the raw score = 57mm

μ is the population mean = 52mm

σ is the population standard deviation = 4mm

z = 57 - 52/4

z = 1.25

Probability value from Z-Table:

P(x<57) = 0.89435

P(x>57) = 1 - P(x<57)

1 - 0.89435

= 0.10565

Approximately = 0.1057

The probability that the diameter of a selected bearing is greater than 57 millimeters is 0.1057

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

answer: ur v dumb

step-by-step explanation: