Mathematics, 04.11.2020 21:40 tylonhouse362

The integers a, b and c are all positive. Given that a + b + c = 14 and 156a + 13 b + c = 873, find 100a + 10b + c.

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Answer from: whittingtondee7084

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Answer from: Quest

l.jnl.j/n.m,lm,

step-by-step explanation:

Answer from: Quest

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is $x^2$ .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒ $x^2=1/2\times ea\times ad$

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

= $(\frac{2\times -7+1\times -10}{2+1},\frac{2\times 2+1\times 8}{2+1})$

= $(\frac{-24}{3}, \frac{12}{3})$

=(-8, 4)

thus the coordinates of a are (-8,4)

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The integers a, b and c are all positive. Given that a + b + c = 14 and 156a + 13 b + c = 873, find...