A scooter travels 30 feet in 2 seconds at a constant speed. The distance the scooter travels in 1 second is
feet. The distance the scooter travels in 3 seconds is
feet. The distance the scooter travels in 4 second is
feet. The distance the scooter travels in 5 second is
feet.

The scooter travels 15 feet in 1 second

The scooter travels 45 feet in 3 seconds

The scooter travels 60 feet in 4 seconds

The scooter travels 75 feet in 5 seconds

Step-by-step explanation:

First, let's find the number of feet the scooter travels in 1 second

(30 : 2) ÷ 2 = 15 : 1

Now that we have the unit rate, we can easily find the answers to the other questions.

(15 : 1) x 3 = 45 : 3

(15 : 1) x 4 = 60 : 4

(15 : 1) x 5 = 75 : 5

I Hope That This Helps! :)

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!