What is the equation of the line that is perpendicular to y minus 3 x = 2 and that passes through (6,1)? On a coordinate plane, a line goes through (0, 2) and (1, 5). A point is at (6, 1).
y = one-third x minus 1
y = one-third x + 3
y = negative one-third x + 3
y = negative one-third x minus 1

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

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. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

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