(3z−6)/(7−2z) = 1.2/3.2 Please help

Step-by-step explanation:

Given the equation (3z−6)/(7−2z) = 1.2/3.2

To get z, we need to cross multiply first

3.2 (3z-6) = 1.2(7-2z)

open the parenthesis

9.6z-19.2 = 8.4 - 2.4z

collect like terms

9.6z + 2.4z = 8.4 + 19.2

12z = 27.6

z = 27.6/12

z = 2.3

Hence the value of z is 2.3

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

for this case we have that by definition, the surface area of a cylinder is given by:

where:

r: it is the radius of the cylinder

h: it is the height of the cylinder

we can also rewrite it as:

where:

la: it's the lateral area

ba: area of the base

option a