Diego is interested in buying a printer. He has a coupon for a discount of 20%. There is a 8% sales tax on the printer. The final price of the printer after the discount is 212.32. What is the original price

use this as a way to solve your problem no the exact equation so look at how i did this and just use ur price after the discount. if you still need help lmk

Step-by-step explanation:

Let P = the original price of the printer

Diego uses his coupon to get 20% off  (reduced by 20% leaves 80% of P that he pays)

Apply 8% tax to .8P

      0.8P ( 1.08) = $103.68

       P = $120.00

Note:  checking your answer is very important !

Checking:

    Price      =  $120.00

    Discount   =   24.00

    Sale price  =   96.00

With tax    1.08*(96) = $103.68

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}