Solve the division problems, and match them to their solutions. 31r 112
31r 8
28r 58
28r 5
6,834 ÷ 242 =

9,105 ÷ 325 =

6,684 ÷ 212 =

8,967 ÷ 289 =

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

step-by-step explanation: the answer for wha if rt is 10 centimeters long, and wha is st? it’s 6