HELP HELP Given kx^2 +(5-k)x+3=0, where k is not equal to zero, find k if one of the roots is 3, then find the other roots

-1

Step-by-step explanation:

kx² + (5-x)k + 3 = 0

kx² + (5-x)k + 3 = (bx - 3)(ax + n)

kx² + (5-x)k + 3 = abx² + (bn - 3a)x -3n

thus -3n = 3 so n = -1

other root = -1

I hope this helps you :)

1. 34

2. 268

3. x=14.4

step-by-step explanation:

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.