Can any kind soul help me please

f(x)= -5

Step-by-step explanation:

Determine the types of roots for quadratic function f(x)= 2x^2 + x - 5 when f(x)= 0. Thus, sketch the graph generally at the x-axis

First, rewrite the equation.

f(x)= 2x^2 + x - 5 Then, subsitute the variables to ZERO (0).

f(0)= 2(0)^2 +  0 - 5

Zero raised to any number is zero.

Remove the zero before -5 because it's unecessary.

f(0)= 2(0) - 5

f(0)= 0 - 5

SIMPLIFY- The final answer is -5

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^