Part A A toy cannon ball is launched from a cannon on top of a platform. The equation h(t) = –5t2 + 30t + 8 gives the height h, in meters, of the ball t seconds after it is launched. What equation can be used to tell whether the ball reaches a height of 34 m?

A. –5t2 + 30t + 8 = 0

B. –5t2 + 30t + 8 = 34

C. –5t2 + 30t + 4 + 34 = 0

D. –5t2 + 30t + 4 = t + 34

Part B

A toy cannon ball is launched from a cannon on top of a platform. The equation h(t) = –5t2 + 30t + 8 gives the height h, in meters, of the ball t seconds after it is launched. Does the ball reach a height of 34 m?

A. yes

B. no

answer: r there any options?

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

c = 0.429t

step-by-step explanation:

the constant rate at which carlos harvests cassava is 35 minutes per 15 cassavas 15/35 = 0.429 cassava per minute

therefore, an equation that models the number of cassava (c) that harvest carlos in a time (t) is the following:

where t is the time in minutes.

this means that when 35 minutes have elapsed 15 cassava have been harvested, at 70 minutes 30 cassava have been harvested and so on.