What is an equation of the line that passes through the points (5, 2) and (-5, -6)?

y = (4/5)x - 2

Step-by-step explanation:

First we must find the slope. This is calculated by dividing the difference of the y-coordinates by the difference of the x-coordinates.

Δ y-coordinates: 2 - (-6) = 2 + 6 = 8

Δ x-coordinates: 5 - (-5) = 5 + 5 = 10

slope = m = 8/10 = 4/5

Now, we can write the line in slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.

Choose (5, 2) (or you can use (-5, -6); it should get you the same answer) to plug into the equation to solve for b:

y = mx + b

2 = (4/5) * 5 + b

b = 2 - 4 = -2

Thus, our equation is y = (4/5)x - 2.

~ an aesthetics lover

a

step-by-step explanation:

ppopibujflnnkjh un

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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