A worker is taking cases of screws on a lift. Each case weighs 47 pounds and the worker weighs 182 pounds. The lift has a weight limit of 2700 write inequality that describes the number of cases he can safely take on each trip. What is the maximum amount of cases he can take?

The inequality is;

47x + 182 ≤ 2,700

where x is number of cases

The maximum amount of cases is 53

Step-by-step explanation:

Here, we want to know the number of cases that will be taken

Let the number of cases be x

Total case weight will be x * 47 = 47x pounds

So adding this to the weight of the worker, we have;

47x + 182 ≤ 2,700

The maximum will be;

47x ≤ 2700-182

47x ≤ 2518

x ≤ 2518/57

x ≤ 53.57

Rounding this to the lower limit will be 53 ( if rounded to 54, it will be higher than maximum weight of lift)

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation: