Exactly 10 disks are in a bowl. Each is marked with a different counting number selected from 1-10. Gina and Monique each select 5 disks. Two of Gina's disks are 2 and 8. Two of Monique's disks are 7 and 9. What is the largest sum that Gina's disks can have?

31

Step-by-step explanation:

The two disks that we know Gina has are: 2 and 8.

We want to find tha largest sum that Gina's disks can have:

This means that the other 3 disks must be the largest possible ones.

We know that Monique has the disks 7 and 9.

The already taken values are: 2, 7, 8, and 9.

The largest values remaining are:

10, 6 and 5.

Then the largest sum that Gyna's disks can have is given by the scenario where Gina draws these 3 disks, and the sum will be:

2 + 8 + 10 + 6 + 5 = 31

add 5 subtract 1

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3