Write equation perpendicular to 3x-5y=6 and passes through (-8, 0)

y = (-5/3)x - 40/3

Step-by-step explanation:

Put the given line in Slope Intercept Form by solving it for y

Use the known relationship between the slopes of perpendicular lines they have inverse slopes of opposite signs.

Plug the points into the Slope Intercept Form of  Perpendicular line to solve for b

First the given line

3x - 5y = 6

-5y = -3x + 6

Divide both sides by negative 5

y = (-3/-5)x - 6/5

y = (3/5)x - 6/5

In Slope Intercept Form is

y = (3/5)x - 6/5

so m = (3/5)

The slope of the Perpendicular would be negative inverse of 3/5 or

m = (-5/3)x

The Slope Intercept form for the perpendicular line is

y = (-5/3)x + b

Use the coordinates (-8,0) to solve for b

0 = (-5/3)(-8) + b

0 = 40/3 + b

Subtract 40/3 from both sides of the equation

-40/3 = b

The perpendicular line is

y = (-5/3)x - 40/3

step- i d k and i d c : )

you: : 0

bye

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: