I NEED HELP WITH THIS PLZ HELP ME WITH MATH! I"M GIVING 20 points for someone who answers it. PLZ HELP ME WITH MATH!

X^8 / 256y^20

Step-by-step explanation:

First to make your life easier with this problem reduce the fraction 5/20 = 1/4

x^3/x = x^3-1= x^2

Then you apply the outer exponent

X^2*4 = X^8

4^4= 256

y^5*4 = y^20

X^8 / 256y^20

70,000 + 6,000 + 800 + 30

step-by-step explanation:

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it