2. How many liters of a 10% alcohol solution and how many liters of a 20% alcohol solution must be mixed together to make 10 L of a 12 % alcohol solution?

x=liters of 20% alcohol solution to be mixed with 60 liters of 90% alcohol solution.

x+60 =liters of 50% alcohol solution

20%x+90%(60)=50%(x+60)

.2x+54=.5x+30

.3x=24

x=80

ans:

80 liters of a 20% alcohol solution must be mixed with 60 L of a 90% alcohol solution to get a 50% alcohol solution.

Step-by-step explanation: there

answer;

the correct answer

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