Ok last one for today that I cant figure out
(6c - 4) - ( c - 3) c = -7 Ty!

9
c
−
4
−
c
2
=
−
7
9
c
-
4
-
c
2
=
-
7
Move
7
7
to the left side of the equation by adding it to both sides.
9
c
−
4
−
c
2
+
7
=
0
9
c
-
4
-
c
2
+
7
=
0

Add
−
4
-
4
and
7
7
.
9
c
−
c
2
+
3
=
0
9
c
-
c
2
+
3
=
0
Factor
−
1
-
1
out of
9
c
−
c
2
+
3
9
c
-
c
2
+
3
.
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−
(
c
2
−
9
c
−
3
)
=
0
-
(
c
2
-
9
c
-
3
)
=
0
Multiply each term in
−
(
c
2
−
9
c
−
3
)
=
0
-
(
c
2
-
9
c
-
3
)
=
0
by
−
1
-
1
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c
2
−
9
c
−
3
=
0
c
2
-
9
c
-
3
=
0
Use the quadratic formula to find the solutions.
−
b
±
√
b
2
−
4
(
a
c
)
2
a
-
b
±
b
2
-
4
(
a
c
)
2
a
Substitute the values
a
=
1
a
=
1
,
b
=
−
9
b
=
-
9
, and
c
=
−
3
c
=
-
3
into the quadratic formula and solve for
c
c
.
9
±
√
(
−
9
)
2
−
4
⋅
(
1
⋅
−
3
)
2
⋅
1
9
±
(
-
9
)
2
-
4
⋅
(
1
⋅
-
3
)
2
⋅
1
Simplify.
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c
=
9
±
√
93
2
c
=
9
±
93
2
The final answer is the combination of both solutions.
c
=
9
+
√
93
2
,
9
−
√
93
2
c
=
9
+
93
2
,
9
-
93
2
The result can be shown in multiple forms.
Exact Form:
c
=
9
+
√
93
2
,
9
−
√
93
2

The answer is