Anna and Bobie joined two different swimming classes at the same time. Anna's swimming school charged an initial amount of $70 and Bobie's charged $250. Their monthly
fees were different.
The total amount paid for in the first t months is given by (PA) for Anna and (PB) for Bobie.
Anna paid $120 and Bobie paid $264 in total for the first two months, but after some months, they
found that they have paid the same amount in total.
After how many months will their total payments be the same and how much will it be?

It would be 10 months for the price of $320.

Step-by-step explanation:

First we need to find how much Anna's swimming charge and Bobie's charge is.

PA=70+t The price of the month equals to the starting fee and monthly charge

120=70+2t The price of 2 months times the monthly charge

50=2t

25=t           is Anna's monthly charge

PB=250+t   is Bobies starting price and monthly charge

264=250+2t is the month charge for Bobie after 2 months

14=2t

7=t              is Bobie's monthly charge

70+25x=250+7x    We need to find x which is what month will satisfy both equations

25x=180+7x         Subtract 70 from both sides

18x=180                Subtract 7x from both sides

x=10                      divide 18 from both sides

Now we have the months that satisfy both equations we need to find the total price that matches with it. So we plug it back into both equations.

PA=70+25x                                               PB=250+7x

PA=70+25(10)                                            PB=250+7(10)

PA=70+250                                               PB=250+70

PA=320                                                      PB=320

It would be 10 months for the price of $320.

Step-by-step explanation:

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°