A backyard pool has a concrete walkway around it that is 3 feet wide on all sides. The total area of the pool and the walkway is 970 ft2. If the length of the pool is 8 feet longer than the width, find the dimensions of the pool.

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step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92

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the answer is -1 for this question

step-by-step explanation: