∠C and ∠D are a linear pair. ∠C is four times larger than ∠D. What is the measure of ∠C?

first we represent the unknowns using variables:

let x = measure of angle 4

let 3x+4 = measure of angle 3 (from the second statement)

then we set-up the equation. since the angles form a linear pair, their sum is equal to 180 degrees. therefore,

x + 3x + 4 = 180

4x + 4 = 180

4x = 176

x = 44 degrees (measure of angle 4)

3x + 4 = 136 degrees (measure of angle 3)

boxplot e is the answer

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v