Find the value of the probability of the standard normal variable Z corresponding to this area for problems 1-3.

Explained below.

Step-by-step explanation:

The complete question is:

Find the value of the probability of the standard normal variable Z corresponding to this area for problems 1-3.

1. P(Z < 1.62)

2. P(Z > -1.57)

3. P(-1.41 < Z < 0.63)

Solution:

Use Excel to solve the problems.

(1)

P(Z < 1.62)  =NORM.S.DIST(1.62,TRUE)

                 = 0.9474

(2)

P(Z > -1.57)  = P (Z < 1.57)

                  =NORM.S.DIST(1.57,TRUE)

                  = 0.9418

(3)

P(-1.41 < Z < 0.63) = P (Z < 0.63) - P (Z < -1.41)

                             =NORM.S.DIST(0.63,TRUE) - NORM.S.DIST(-1.41,TRUE)

                             = 0.7357 - 0.0793

                             = 0.6564

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb